document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335856>Question 335856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a 10% solution of fertilizer is to be mixed with a 50% solution of fertilizer in order to get 160 gallons of 40% solution. How many gallons of the 10% solution and the 50% solution should be mixed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240880 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let 10 % be x <BR>\n" );
document.write( "50 % will be 160-x<BR>\n" );
document.write( "Mixture 40% 160 liters<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Concentration equation<BR>\n" );
document.write( "..<BR>\n" );
document.write( "0.1x+0.5(160-x)= 160*.4<BR>\n" );
document.write( "0.1x +80-0.5x = 64 <BR>\n" );
document.write( "-0.4x = -80+64<BR>\n" );
document.write( "-0.4x = -16<BR>\n" );
document.write( "divide by -0.4<BR>\n" );
document.write( "x= -16/-0.4<BR>\n" );
document.write( "x=40 liters 10% solution<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );