document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335849>Question 335849</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one third of a number is added to 4, with a result of at least 2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240869 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the number<BR>\n" );
document.write( "x/3 +4 >=2<BR>\n" );
document.write( "add -4 to both sides<BR>\n" );
document.write( "x/3 +4-4 >=2-4<BR>\n" );
document.write( "x/3 >=-2<BR>\n" );
document.write( "multiply by 3<BR>\n" );
document.write( "x/3 * 3 >= 2*-2<BR>\n" );
document.write( "x>=-4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );