document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335772>Question 335772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give reasons for the steps in the following proof:<BR>\n" );
document.write( "If 3x + (-1)=0, then x= 1/3.\r<BR>\n" );
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document.write( "1. 3x+(-1)=0           1.Given<BR>\n" );
document.write( "2. [3x+(-1)+1=0+1      2.<BR>\n" );
document.write( "3. 3x+[(-1)+1]=0+1     3.<BR>\n" );
document.write( "4. 3x+0=0+1            4.<BR>\n" );
document.write( "5. 3x=1                5.<BR>\n" );
document.write( "6. 1/3(3x)=1/3(1)      6.<BR>\n" );
document.write( "7. (1/3*3)x=1/3(1)     7.<BR>\n" );
document.write( "8. 1*x=1/3*1           8.<BR>\n" );
document.write( "9. x=1/3               9. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240808 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Given<BR>\n" );
document.write( "2. Add 1 to both sides<BR>\n" );
document.write( "3. Same as 2 brackets are not required.<BR>\n" );
document.write( "4. Additive inverse property.<BR>\n" );
document.write( "5. Identity property.<BR>\n" );
document.write( "6. Divide both sides by 3.<BR>\n" );
document.write( "7. Commutative property.<BR>\n" );
document.write( "8. Multiplicative inverse property.<BR>\n" );
document.write( "9. Identity property. </SPAN>\n" );
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