document.write( "Question 335790: driving from town A to town D, you pass thru town B then town C. town A to town B is 10 miles farther than from town B to town C. town B to town C is 10 miles farther than from town C to town D. if town A is 390 miles from town D, how many mile is town A to town B??\r
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document.write( "A-------B-------C-------D
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document.write( ".-------------------------.=390
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document.write( "390/3=130
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document.write( "answer is 140 mi; just can't explain or show method; could you help? \n" );
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Algebra.Com's Answer #240805 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! driving from town A to town D, you pass thru town B then town C. \n" ); document.write( "------------------------ \n" ); document.write( "town A to town B is 10 miles farther than from town B to town C. \n" ); document.write( "town B to town C is 10 miles farther than from town C to town D. \n" ); document.write( "--------------------------- \n" ); document.write( "if town A is 390 miles from town D, how many mile is town A to town B?? \r \n" ); document.write( "\n" ); document.write( "A-------B-------C-------D \n" ); document.write( ".-------------------------.=390 \n" ); document.write( "========================================= \n" ); document.write( "Let dist. from B to C be \"x\" miles. \n" ); document.write( "Then dist. from A to B is \"x+10\" miles. \n" ); document.write( "And dist. from C to D is \"x -10\" miles \n" ); document.write( "=========================================== \n" ); document.write( "Equation: \n" ); document.write( "x+10 + x + x-10 = 390 \n" ); document.write( "3x = 390 \n" ); document.write( "x = 130 miles \n" ); document.write( "---- \n" ); document.write( "A to B = x+10 = 140 \n" ); document.write( "B to C = x = 130 \n" ); document.write( "C to D = x-10 = 120 \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========================= \n" ); document.write( " |