document.write( "Question 335790: driving from town A to town D, you pass thru town B then town C. town A to town B is 10 miles farther than from town B to town C. town B to town C is 10 miles farther than from town C to town D. if town A is 390 miles from town D, how many mile is town A to town B??\r
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\n" ); document.write( "\n" ); document.write( "A-------B-------C-------D
\n" ); document.write( ".-------------------------.=390
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\n" ); document.write( "390/3=130
\n" ); document.write( "answer is 140 mi; just can't explain or show method; could you help?
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Algebra.Com's Answer #240803 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
AB-Distance from A to B
\n" ); document.write( "BC-Distance from B to C
\n" ); document.write( "CD-Distance from C to D
\n" ); document.write( "AD-Distance from A to D
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\n" ); document.write( "\"AB=10%2BBC\"
\n" ); document.write( "\"BC=10%2BCD\"
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\n" ); document.write( "\"AD=390\"
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\n" ); document.write( ".
\n" ); document.write( "\"AD=AB%2BBC%2BCD\"
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\n" ); document.write( "Substitute from above,
\n" ); document.write( "\"AD=10%2BBC%2B10%2BCD%2BCD\"
\n" ); document.write( "Substitute again for \"BC\"
\n" ); document.write( "\"AD=10%2B%2810%2BCD%29%2B10%2BCD%2BCD=390\"
\n" ); document.write( "Solve for \"CD\".
\n" ); document.write( "\"3CD%2B30=390\"
\n" ); document.write( "\"3CD=360\"
\n" ); document.write( "\"CD=120\"
\n" ); document.write( "Now work backwards,
\n" ); document.write( "\"BC=10%2BCD%7D%7D%0D%0A%7B%7B%7BBC=10%2B120=130\"
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\n" ); document.write( "\"AB=10%2BBC\"
\n" ); document.write( "\"AB=10%2B130=highlight%28140%29\"
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