document.write( "Question 335756: A toolbox is 2 ft high, and its width is 3 ft less than its length. If the volume is 80ft^3, find the length and width of the box. I do not understand how to solve this problem. The book eplains it in a very confusing way. \n" ); document.write( "
Algebra.Com's Answer #240792 by Fombitz(32388)\"\" \"About 
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The volume of the toolbox is,
\n" ); document.write( "\"V=L%2AW%2AH=80\"
\n" ); document.write( "\"H=2\"
\n" ); document.write( "\"W=L-3\"
\n" ); document.write( "Substitute into the volume equation,
\n" ); document.write( "\"L%2A%28L-3%29%2A2=80\"
\n" ); document.write( "\"L%28L-3%29=40\"
\n" ); document.write( "\"L%5E2-3L-40=0\"
\n" ); document.write( "Factor this quadratic equation,
\n" ); document.write( "\"%28L-8%29%28L%2B5%29=0\"
\n" ); document.write( "Only positive solutions for L are appropriate.
\n" ); document.write( "\"L-8=0\"
\n" ); document.write( "\"highlight%28L=8%29\"
\n" ); document.write( "Then from above,
\n" ); document.write( "\"W=L-3\"
\n" ); document.write( "\"W=8-3\"
\n" ); document.write( "\"highlight%28W=5%29\"
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