document.write( "Question 335775: How many liters of a 60% alcohol solution must be mixed with 50 liters of a 90% solution to get a 70% solution? \n" ); document.write( "
Algebra.Com's Answer #240782 by stanbon(75887)\"\" \"About 
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How many liters of a 60% alcohol solution must be mixed with 50 liters of a 90% solution to get a 70% solution?
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\n" ); document.write( "Equation:
\n" ); document.write( "alcohol+ alcohol = alcohol
\n" ); document.write( "0.60x + 0.90*50 = 0.70(x+50)
\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "60x + 90*50 = 70x + 70*50
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\n" ); document.write( "-10x = -20*50
\n" ); document.write( "x = 100 liters (amt. of 60% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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