document.write( "Question 335775: How many liters of a 60% alcohol solution must be mixed with 50 liters of a 90% solution to get a 70% solution? \n" ); document.write( "
Algebra.Com's Answer #240782 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How many liters of a 60% alcohol solution must be mixed with 50 liters of a 90% solution to get a 70% solution? \n" ); document.write( "-------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol+ alcohol = alcohol \n" ); document.write( "0.60x + 0.90*50 = 0.70(x+50) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "60x + 90*50 = 70x + 70*50 \n" ); document.write( "------ \n" ); document.write( "-10x = -20*50 \n" ); document.write( "x = 100 liters (amt. of 60% solution needed in the mixture) \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |