document.write( "Question 335730: Find two consecutive odd integers such that five times their sum is 23 less than their product. This is how i tried to solve it, but i think that i am missing a step.
\n" ); document.write( "x(x+2)= 5(x+x+2)-23
\n" ); document.write( "x^2+2x=5x+5x+10-23
\n" ); document.write( "x^2+2x=10x-13
\n" ); document.write( "x^2-8x-13\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #240758 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You should have the equation \"5%28x%2Bx%2B2%29=x%28x%2B2%29-23\" \n" ); document.write( "
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