document.write( "Question 335703: I need help on this problem:
\n" ); document.write( "An object's altitude, in meters, is given by the polynomial h + vt - 9.8t2, where h is the height in meters from which the launch occurs, v is the initial upward speed in meters per second, and t is the number of seconds for which the rocket is airborne. A pebble is shot upward from the top of a building 190 meters tall. If the initial speed is 40 meters per second, how high above the ground will the pebble be after 2 seconds? Round results to the nearest tenth of a meter.
\n" ); document.write( "

Algebra.Com's Answer #240756 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "No! No! No!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Unless you are on a different planet than Earth, an object's altitude in meters is given by:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "where is initial velocity and is initial height.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now that you have the correct height function, all you need to do is substitute 190 for , 40 for , and 2 for and then do the arithmetic.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );