document.write( "Question 38430: Graphing Linear Equations:
\n" ); document.write( "Draw the graph of each equation:
\n" ); document.write( "3x-4y=12
\n" ); document.write( "y=2x
\n" ); document.write( "y-6=0
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Algebra.Com's Answer #24073 by lyra(94)\"\" \"About 
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Please only put one question per submission. Try to use the solver below for your other problems, if you still need help don't hesitate to contact me.\r
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"3+x+%2B+-4+y+=+12\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+-3%2F-4\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 12/3 = 4.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 12/-4 = -3.
  • Slope is -3/-4 = 0.75.
  • Equation in slope-intercept form: y=0.75*x+-3.
\"graph%28+500%2C+500%2C+4-8%2C+4%2B8%2C+-3-8%2C+-3%2B8%2C+0.75%2Ax%2B-3+%29+\"\n" ); document.write( "

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\n" ); document.write( "\n" ); document.write( "Hope this helps and feel free to contact me with further questions,
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