document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335701>Question 335701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On average it takes 0.6 of a second to count a single digit number, 0.8 of a second to count a  2-digit number, 1.2 seconds to count a 3-digit number, 2.1 seconds to count a 4-digit number, 2.4 seconds to count a 5-digit number, 3.0 seconds to count a  6-digit number, and 0.8 of a second to count the number 1 million.  If two friends take turns counting and sleeping so that no time  is wasted, how long will it take them to count from one to one million?\r<BR>\n" );
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document.write( "I thought if I took the average of all the numbers 0.6+0.8+1.2+2.1+2.4+3.0+0.8=10.9 /7 1.55 or 2seconds per number <BR>\n" );
document.write( "then there are 86,400 seconds in a day or (60*60*24) so I thought that 2,000,000/86400=23.1 days  is that right??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240722 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Nope.\r<BR>\n" );
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document.write( "There are only 9 one-digit numbers (if you start from 1)\r<BR>\n" );
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document.write( "Then there are 90 two-digit numbers\r<BR>\n" );
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document.write( "Then there are 900 three digit numbers...\r<BR>\n" );
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document.write( "You should start seeing the pattern by now.\r<BR>\n" );
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document.write( "So you need 9 times 0.6 plus 90 times 0.8 plus 900 times 1.2, and so on.  Finish up with 1 times 0.8.  All that gets you the number of seconds which you need to divide by 86,400. The answer you gave was only about 2/3 of the correct answer.  Write back and let me know what you got.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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