document.write( "Question 335573: A is two-thirds the way from (1,10) to (-8,4) and B is the midpoint of (0,-7) (6,-11).find the distance AB? \n" ); document.write( "
Algebra.Com's Answer #240704 by Fombitz(32388)\"\" \"About 
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Find the coordinates of A.
\n" ); document.write( "x coordinate: \"x=x1%2B%282%2F3%29%28x2-x1%29=1%2B%282%2F3%29%28-8-1%29=1-6=-5\"
\n" ); document.write( "y coordinate: \"y=y1%2B%282%2F3%29%28y2-y1%29=10%2B%282%2F3%29%284-10%29=10-4=6\"
\n" ); document.write( "A:(\"-5\",\"6\")
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\n" ); document.write( "Find the midpoint of (0,-7) and (6,-11)
\n" ); document.write( "\"xm=%28x1%2Bx2%29%2F2=%280%2B6%29%2F2\"
\n" ); document.write( "\"ym=%28y1%2By2%29%2F2=%28-7-11%29%2F2\"
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\n" ); document.write( "Complete the calculation to find the midpoint.
\n" ); document.write( "Then use the distance formula to calculate AB.
\n" ); document.write( "\"AB%5E2=%28-5-xm%29%5E2%2B%286-ym%29%5E2\"
\n" ); document.write( "\"AB=sqrt%28%28-5-xm%29%5E2%2B%286-ym%29%5E2%29\"
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