document.write( "Question 335696: I am having a hard time figuring this word problem out. Can you please help.
\n" ); document.write( "Upstream, downstream. Junior’s boat will go 15 miles per
\n" ); document.write( "hour in still water. If he can go 12 miles downstream in the
\n" ); document.write( "same amount of time as it takes to go 9 miles upstream,
\n" ); document.write( "then what is the speed of the current?
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Algebra.Com's Answer #240698 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Junior’s boat will go 15 miles per hour in still water.
\n" ); document.write( "If he can go 12 miles downstream in the
\n" ); document.write( "same amount of time as it takes to go 9 miles upstream,
\n" ); document.write( "then what is the speed of the current?
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\n" ); document.write( "Downstream DATA:
\n" ); document.write( "distance = 12 miles ; rate = 15+c mph ; time = d/r = 12/(15+c) hrs
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\n" ); document.write( "Upstream DATA:
\n" ); document.write( "distance = 9 miles ; rate = 15-c mph ; time = d/r = 9/(15-c) hrs
\n" ); document.write( "--------------------
\n" ); document.write( "Equation:
\n" ); document.write( "time up = time down
\n" ); document.write( "8/(15-c) = 12/(15+c)
\n" ); document.write( "9(15+c) = 12(15-c)
\n" ); document.write( "9*15+9c = 12*15-12c
\n" ); document.write( "21c = 3(15)
\n" ); document.write( "c = (1/7)15
\n" ); document.write( "c = 2.5 mph (speed of the current)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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