document.write( "Question 335696: I am having a hard time figuring this word problem out. Can you please help.
\n" ); document.write( "Upstream, downstream. Junior’s boat will go 15 miles per
\n" ); document.write( "hour in still water. If he can go 12 miles downstream in the
\n" ); document.write( "same amount of time as it takes to go 9 miles upstream,
\n" ); document.write( "then what is the speed of the current?
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Algebra.Com's Answer #240692 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
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\n" ); document.write( "Let's call the speed of the current C.
\n" ); document.write( "When you go downstream, you add the speed of the boat and the current,
\n" ); document.write( "1.\"%2815%2BC%29t=12\"
\n" ); document.write( "When you go upstream, you subtract the current from the boat speed,
\n" ); document.write( "2.\"%2815-C%29t=9\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"t=12%2F%2815%2BC%29\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"%2815-C%29%2A%2812%2F%2815%2BC%29%29=9\"
\n" ); document.write( "\"12%2815-C%29=9%2815%2BC%29\"
\n" ); document.write( "\"180-12C=135%2B9C\"
\n" ); document.write( "\"-21C=-45\"
\n" ); document.write( "\"C=45%2F21=15%2F7\" mph
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