document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335640>Question 335640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me understand how to solve these equations by the addition method.\r<BR>\n" );
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document.write( "Many thanks.\r<BR>\n" );
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document.write( "2x = 2-y<BR>\n" );
document.write( "3x + y = -1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240681 by </B><A HREF=/tutors/aboutme.mpl?userid=MarionR55><B>MarionR55(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MarionR55><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240681\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x = 2-y<BR>\n" );
document.write( "3x + y = -1<BR>\n" );
document.write( "move everything to the left hand side of the equation\r<BR>\n" );
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document.write( "2x + y - 2 = 0<BR>\n" );
document.write( "3x + y + 1 = 0\r<BR>\n" );
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document.write( "now you want to add the lines together to get rid of the y yet they are bot positive so multiply by -1\r<BR>\n" );
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document.write( "-2x -y + 2 = 0<BR>\n" );
document.write( "3x + y + 1 = 0  now add the lines together<BR>\n" );
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document.write( "x + 3 = 0        solve for x\r<BR>\n" );
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document.write( "x= -3  now substitute -3 back in to the above equations and solve for y<BR>\n" );
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