document.write( "Question 38555: Solve the linear system: x+2y= 1
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\n" ); document.write( " -x+y= -1 \n" ); document.write( "
Algebra.Com's Answer #24068 by lyra(94)\"\" \"About 
You can put this solution on YOUR website!
Here's two ways to solve your problem:
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Solved by pluggable solver: Linear System solver (using determinant)
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+2%5Cy+=+1%2C%0D%0A++++-1%5Cx+%2B+1%5Cy+=+-1+%29%0D%0A++\"
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\n" ); document.write( " Any system of equations:
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\n" ); document.write( " has solution
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\n" ); document.write( " (x=1, y=0}
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Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
\n" ); document.write( " \"+system%28+%0D%0A++++1%5Cx+%2B+2%5Cy+=+1%2C%0D%0A++++-1%5Cx+%2B+1%5Cy+=+-1+%29%0D%0A++\"We'll use substitution. After moving 2*y to the right, we get:
\n" ); document.write( " \"1%2Ax+=+1+-+2%2Ay\", or \"x+=+1%2F1+-+2%2Ay%2F1\". Substitute that
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\n" ); document.write( " \"-1%2A%281%2F1+-+2%2Ay%2F1%29+%2B+1%5Cy+=+-1\" and simplify: So, we know that y=0. Since \"x+=+1%2F1+-+2%2Ay%2F1\", x=1.
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\n" ); document.write( " Answer: \"system%28+x=1%2C+y=0+%29\".
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\n" ); document.write( "\n" ); document.write( "Hope this helps and feel free to contact me with further questions,
\n" ); document.write( "lyra
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