document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335532>Question 335532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On a weekend trip you average 35 miles per hour in the city and 60 miles per hour on the highway. If the 150 mile               trip took 3 hours how much of the time were you droning in the city </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240649 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let C = hours in city<BR>\n" );
document.write( "Let H = hours on highway\r<BR>\n" );
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document.write( "35C + 60H = 150<BR>\n" );
document.write( "C + H = 3\r<BR>\n" );
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document.write( "Let's solve this by eliminating H.<BR>\n" );
document.write( "Multiply both sides of the second equation by 60:<BR>\n" );
document.write( "60C + 60H = 180\r<BR>\n" );
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document.write( "Now subtract the original first equation:<BR>\n" );
document.write( "(60C + 60H) - (35C + 60H) = 180 - 150\r<BR>\n" );
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document.write( "Simplify by combining like terms:<BR>\n" );
document.write( "25C = 30\r<BR>\n" );
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document.write( "Divide both sides by 25:<BR>\n" );
document.write( "C = 30/25 = 6/5 hours, which is 72 minutes, or 1 1/5 hours, or 1 hour and 12 minutes, which is the same thing as 72 minutes. </SPAN>\n" );
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