document.write( "Question 335532: On a weekend trip you average 35 miles per hour in the city and 60 miles per hour on the highway. If the 150 mile trip took 3 hours how much of the time were you droning in the city \n" ); document.write( "
Algebra.Com's Answer #240634 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Rate*Time=Distance
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "In the city,
\n" ); document.write( "\"35%2AT1=D1\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "On the highway,
\n" ); document.write( "\"60%2AT2=D2\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"D1%2BD2=150\"
\n" ); document.write( "1.\"35T1%2B60T2=150\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "2.\"T1%2BT2=3\"
\n" ); document.write( "From eq. 2,
\n" ); document.write( "\"T2=3-T1\"
\n" ); document.write( "Substitute into eq. 1,
\n" ); document.write( "\"35T1%2B60%283-T1%29=150\"
\n" ); document.write( "\"35T1%2B180-60T1=150\"
\n" ); document.write( "\"-25T1=-30\"
\n" ); document.write( "\"T1=6%2F5\"hr
\n" ); document.write( "\"T1=%286%2F5%29%2860%29=72\" minutes
\n" ); document.write( "
\n" );