document.write( "Question 335410: What quantity of 60 per cent acid solution must be mixed with a 25 solution to produce 168 mL of a 50 per cent solution?
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Algebra.Com's Answer #240577 by Fombitz(32388) $\"\"$ $\"About$

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Let A be the amount of 60% solution, B the amount of 25% solution.
\n" ); document.write( "1. $\"A%2BB=168\"$
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\n" ); document.write( " $\"60A%2B25B=50%28168%29\"$
\n" ); document.write( " $\"60A%2B25B=8400\"$
\n" ); document.write( "2. $\"12A%2B5B=1680\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"A=168-B\"$
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( " $\"12%28168-B%29%2B25B=1680\"$
\n" ); document.write( " $\"2016-12B%2B5B=1680\"$
\n" ); document.write( " $\"-7B=-336\"$
\n" ); document.write( " $\"highlight%28B=48%29\"$ ml
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( " $\"A%2B48=168\"$
\n" ); document.write( " $\"highlight%28A=120%29\"$ ml \n" ); document.write( "

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