document.write( "Question 335567: The usual life of a computer terminal at a university computer center is known to be normally distributed with a mean of 3.25 years and a standard deviation of .5 years.\r
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document.write( "A. What proportion of computer terminals will have a useful life of at least 3 years?
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document.write( "B. Historically, 20% of the terminals have had a useful life less than the manufacture's advertised life. What is the manufacture's advertised life for the computer terminals? \n" );
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Algebra.Com's Answer #240573 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The usual life of a computer terminal at a university computer center is known to be normally distributed with a mean of 3.25 years and a standard deviation of .5 years. \n" ); document.write( "A. What proportion of computer terminals will have a useful life of at least 3 years? \n" ); document.write( "z(3) = (3-3.25)/0.5 = -1/2 \n" ); document.write( "---- \n" ); document.write( "P(x >= 3) = P(z > -1/2) = normalcdf(-1/2,1000) = 0.6915 \n" ); document.write( "------------------------------------------------------------------ \n" ); document.write( "B. Historically, 20% of the terminals have had a useful life less than the manufacture's advertised life. What is the manufacture's advertised life for the computer terminals \n" ); document.write( "--- \n" ); document.write( "Draw a normal curve with u = 3.25 \n" ); document.write( "Find a point that has 20% of the population below 3.25 \n" ); document.write( "That point has a left-tail of 30%. \n" ); document.write( "--- \n" ); document.write( "Find the z-value with a 30% left-tail. \n" ); document.write( "invNorm(0.30) = -0.5244 \n" ); document.write( "-- \n" ); document.write( "Find the corresponding raw score value: \n" ); document.write( "x = zs+u \n" ); document.write( "x = -0.5244*0.5+3.25 \n" ); document.write( "x = 2.9878 \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |