document.write( "Question 335549: solve the equation 4^x+2=3(2^x) by substituting 2^x=y \n" ); document.write( "
Algebra.Com's Answer #240571 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"y=2%5Ex\"
\n" ); document.write( "\"y%5E2=%282%5Ex%29%5E2=2%5E%282x%29=4%5Ex\"\r
\n" ); document.write( "\n" ); document.write( "Substituting,
\n" ); document.write( "\"y%5E2%2B2=3y\"
\n" ); document.write( "\"y%5E2-3y%2B2=0\"
\n" ); document.write( "\"%28y-1%29%28y-2%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"y-1=0\"
\n" ); document.write( "\"y=1\"
\n" ); document.write( "\"2%5Ex=1\"
\n" ); document.write( "\"highlight%28x=0%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"y-2=0\"
\n" ); document.write( "\"y=2\"
\n" ); document.write( "\"2%5Ex=2\"
\n" ); document.write( "\"highlight%28x=1%29\"
\n" ); document.write( "
\n" );