document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335586>Question 335586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measure of two complementary angles exceeds the difference of their measures by 86 degrees . find the measure of each angle ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240556 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The sum of the measure of two complementary angles exceeds the difference of their measures by 86 degrees . find the measure of each angle ?<BR>\n" );
document.write( "----------<BR>\n" );
document.write( "Let one of the complementary angles be \"x\".<BR>\n" );
document.write( "Then the other is \"90-x\".<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x + (90-x) = x-(90-x)+86<BR>\n" );
document.write( "90 = x-90+x+86<BR>\n" );
document.write( "180 = 2x+86<BR>\n" );
document.write( "2x = 94<BR>\n" );
document.write( "x = 47<BR>\n" );
document.write( "90-x = 43<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "=============== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );