document.write( "Question 335571: Mister \"W\" took 20 minutes to drive his boat upstream to his favorite fishing place. His return trip home( downstream) at the same boat speed took him 10 minutes. the current in this part of the river is 3 mph. How far away is his favorite fishing place?
\n" ); document.write( "I tried this X.20min=30min.mph
\n" ); document.write( "X=3/2
\n" ); document.write( "d=30 mile \n" ); document.write( "

Algebra.Com's Answer #240540 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
let the speed in still water be x mph
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\n" ); document.write( "time taken = 20/60 = 1/3 hours
\n" ); document.write( "speed upstream = x-3
\n" ); document.write( "distance = speed * time
\n" ); document.write( "distance = (x-3)*1/3
\n" ); document.write( "..
\n" ); document.write( "down stream speed = x+3
\n" ); document.write( "time = 10/60 = 1/6 hours
\n" ); document.write( "..
\n" ); document.write( "distance = (x+3)*1/6
\n" ); document.write( "..
\n" ); document.write( "1/6*(x+3)=1/3*(x-3)
\n" ); document.write( "3*(x+3)=6*(x-3)
\n" ); document.write( "3x+9 = 6x-18
\n" ); document.write( "-6x+3x = -9-18
\n" ); document.write( "-3x=-27
\n" ); document.write( "x= 9
\n" ); document.write( "x= 9 mph
\n" ); document.write( "...
\n" ); document.write( "speed upstream = 9-3= 6 mph
\n" ); document.write( "time taken =1/3 hours
\n" ); document.write( "Distance = 1/3 * 6 = 2 miles.
\n" ); document.write( " \n" ); document.write( "

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