document.write( "Question 335511: One number is 9 times a first number. A third number is 100 times more than the first number. If the sum of the three numbers is 683, find the numbers \n" ); document.write( "

Algebra.Com's Answer #240512 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's call the numbers A,B and C.
\n" ); document.write( " $\"B=9A\"$
\n" ); document.write( " $\"C=100A\"$
\n" ); document.write( " $\"A%2BB%2BC=683\"$
\n" ); document.write( "Substitute,
\n" ); document.write( " $\"A%2B9A%2B100A=683\"$
\n" ); document.write( " $\"110A=683\"$
\n" ); document.write( " $\"highlight%28A=683%2F110%29\"$
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"B=9%28683%2F110%29\"$
\n" ); document.write( " $\"highlight%28B=6147%2F110%29\"$
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( " $\"C=100%28683%2F110%29\"$
\n" ); document.write( " $\"highlight%28C=6830%2F11%29\"$ \n" ); document.write( "

\n" );