document.write( "Question 4900: The altitude of a triangle is how many times the altitude of a rectangle if the rectangle and the triangle have equal bases and equal areas? \n" ); document.write( "

Algebra.Com's Answer #2405 by Abbey(339) $\"\"$ $\"About$

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The area of a rectangle is length * width (A=LW)
\n" ); document.write( "The area of a triangle is one-half the base * height (A=1/2bh)\r
\n" ); document.write( "\n" ); document.write( "If the triangle area = rectangle area, then
\n" ); document.write( "LW=1/2bh\r
\n" ); document.write( "\n" ); document.write( "and if b=w,we can substitute b for w, in the equation:
\n" ); document.write( "bw=1/2bh\r
\n" ); document.write( "\n" ); document.write( "divide both sides by b:
\n" ); document.write( "w=1/2h\r
\n" ); document.write( "\n" ); document.write( "multiply both sides by 2, to get the answer in terms of the triangle altitude:
\n" ); document.write( "2w=h
\n" ); document.write( "so the altitude of the triangle is 2 times the altitude of the rectangle. \n" ); document.write( "

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