document.write( "Question 335471: The proportion of individuals insured by the All-Driver Automobile Insurance Company who received at least one traffic ticket during a five-year period is .15.\r
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document.write( "Show the sampling distribution of –p if a random sample of 150 insured individuals is use to estimate the proportion having received at least one ticket.\r
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document.write( "What is the probability that the sample proportion will be within +or- .03 of the population proportion?
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Algebra.Com's Answer #240444 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The proportion of individuals insured by the All-Driver Automobile Insurance Company who received at least one traffic ticket during a five-year period is .15. \n" ); document.write( "p = 0.15 \n" ); document.write( "std = sqrt(pq) = sqrt(0.15*0.85) = 0.3571 \n" ); document.write( "------------------------------ \n" ); document.write( "Show the sampling distribution of p-hat if a random sample of 150 insured individuals is used to estimate the proportion having received at least one ticket. \n" ); document.write( "mean = 0.15 \n" ); document.write( "standard deviation: sqrt(pq/n)= sqrt{0.15*0.85/150) = 0.0292 \n" ); document.write( "-------------------------------------------------------- \n" ); document.write( "What is the probability that the sample proportion will be within +or- .03 of the population proportion? \n" ); document.write( "--- \n" ); document.write( "0.03/0.0292 = 1.0290 \n" ); document.write( "-0.03/0.0292 = -1.0290 \n" ); document.write( "--------------------------- \n" ); document.write( "+0.03 is 1.0290 standard deviations to the right of p=0.15 \n" ); document.write( "-0.03 is 1.0292 standard deviations to the left of p= 0.15 \n" ); document.write( "---------------------------- \n" ); document.write( "The probability the sample proportion will be in the prescribed \n" ); document.write( "interval is 2*P(0<= z <=1.0292) = 0.6966 \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |