document.write( "Question 335481: find 2 consecutive integers whose sum is 16 less than the square of the larger number.
\n" ); document.write( " i'm not sure if i set it up right. \r
\n" ); document.write( "\n" ); document.write( "this is how i set it up : x+x+1=\"+sqrt+%28x%2B1%29+\" -16
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Algebra.Com's Answer #240437 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let the two cosequtive integers be x & x+1
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\n" ); document.write( "x+x+1 = (x+1)^2-16
\n" ); document.write( "2x+1=x^2+2x+1-16
\n" ); document.write( "add -2x to both sides
\n" ); document.write( "2x+1-2x=x^2+2x-2x-16+1
\n" ); document.write( "1=x^2+1-16
\n" ); document.write( "add -1
\n" ); document.write( "x^2-16=0
\n" ); document.write( "(x+4)(x-4)=0
\n" ); document.write( "x=-4 or +4
\n" ); document.write( "The integers are -4,-5 OR 4,5
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