document.write( "Question 335481: find 2 consecutive integers whose sum is 16 less than the square of the larger number.
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document.write( " i'm not sure if i set it up right. \r
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document.write( "this is how i set it up : x+x+1= -16 \n" );
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Algebra.Com's Answer #240437 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the two cosequtive integers be x & x+1 \n" ); document.write( ".. \n" ); document.write( "x+x+1 = (x+1)^2-16 \n" ); document.write( "2x+1=x^2+2x+1-16 \n" ); document.write( "add -2x to both sides \n" ); document.write( "2x+1-2x=x^2+2x-2x-16+1 \n" ); document.write( "1=x^2+1-16 \n" ); document.write( "add -1 \n" ); document.write( "x^2-16=0 \n" ); document.write( "(x+4)(x-4)=0 \n" ); document.write( "x=-4 or +4 \n" ); document.write( "The integers are -4,-5 OR 4,5 \n" ); document.write( " |