document.write( "Question 335464: The attendance at a moving theater on a certain day was 737 persons. If there were 289 more adults than children, how many children were there? \n" ); document.write( "
Algebra.Com's Answer #240436 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! C+C+289=737 \n" ); document.write( "2C=737-289 \n" ); document.write( "2C=448 \n" ); document.write( "C=448/2 \n" ); document.write( "C=224 CHILDREN. \n" ); document.write( "224+289=513 ADULTS. \n" ); document.write( "PROOF: \n" ); document.write( "224+513=737 \n" ); document.write( "737=737 \n" ); document.write( " |