document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38541>Question 38541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I add imaginary numbers that are square roots, do I convert first to i then add? Example= sqrt(-9) + sqrt (-36) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24039 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Properly, you pull the i's out first...like this...<BR>\n" );
document.write( "sqrt(-9) + sqrt(-36) =<BR>\n" );
document.write( "i*sqrt(9) + i*sqrt(36) =<BR>\n" );
document.write( "3i + 6i =<BR>\n" );
document.write( "9i<BR>\n" );
document.write( "You could however, merely evaluate the roots initially as 3i and 6i and then add, but properly it is done as above... </SPAN>\n" );
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