document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335341>Question 335341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12. Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.<BR>\n" );
document.write( "The area of a circle is 45 square meters. What is its circumference? (Use &#1087; = 3.14. Hint: Area of Circle: A = &#1087;r2 and Circumference of Circle: C = 2&#1087;r)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240380 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 45=pir^2<BR>\n" );
document.write( "45=3.14*r^2<BR>\n" );
document.write( "r^2=45/3.14<BR>\n" );
document.write( "r^2=14.33<BR>\n" );
document.write( "r=sqrt13.33<BR>\n" );
document.write( "r=3.79 meters ans<BR>\n" );
document.write( "c=2pir<BR>\n" );
document.write( "c=2*3.14*3.79<BR>\n" );
document.write( "c=2*11.9<BR>\n" );
document.write( "c=23.8 meters ans. for the circumferance. </SPAN>\n" );
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