document.write( "Question 335223: x/2 + x/5 = 5/4
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document.write( "can I see this problem worked out and then checked? \n" );
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Algebra.Com's Answer #240275 by CharlesG2(834)![]() ![]() ![]() You can put this solution on YOUR website! x/2 + x/5 = 5/4 \n" ); document.write( "can I see this problem worked out and then checked?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x/2 + x/5 = 5/4 \n" ); document.write( "on left side we need common denominators\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5/5 * x/2 + 2/2 * x/5 = 5/4 (we actually multiplying each fraction by one, so no change in values is actually done)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(5x)/10 + (2x)/10 = 5/4 \n" ); document.write( "(7x)/10 = 5/4 \n" ); document.write( "7x = 5/4 * 10 (multiplied both sides by 10) \n" ); document.write( "7x = 50/4 \n" ); document.write( "28x = 50 (multiplied both sides by 4) \n" ); document.write( "x = 50/28 = 25/14 = 1.7857 rounded to 4 places\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "check: (25/14)/2 + (25/14)/5 \n" ); document.write( "25/14 * 1/2 + 25/14 * 1/5 = 25/28 + 25/70 (need common denominators, 28 goes into 140 five times and 70 goes into 140 two times) \n" ); document.write( "25/28 * 5/5 + 25/70 * 2/2 = 125/140 + 50/140 = 175/140 \n" ); document.write( "175/140 = 35/28 = 5/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 25/14 = 1.7857 rounded to 4 places is indeed the solution\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |