document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=38460>Question 38460</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0812376455/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> x= 2y-1   and 2x+y=81\r<BR>\n" );
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document.write( "solve using substitution\r<BR>\n" );
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document.write( "x=?<BR>\n" );
document.write( "y=?\r<BR>\n" );
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document.write( "show work please thank you!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #24027 by </B><A HREF=/tutors/aboutme.mpl?userid=prabhjyot><B>prabhjyot(165)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prabhjyot><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=24027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">       1x-2y = -1<BR>\n" );
document.write( "      2x+y = 81\r<BR>\n" );
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document.write( "Using Substitution Method.\r<BR>\n" );
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document.write( "Expressing x as a function of y (from the first equation) x = (-1 +2y)/1\r<BR>\n" );
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document.write( "Substituting this expression into the second equation:\r<BR>\n" );
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document.write( "	2(-1-2y)/1+y = 81\r<BR>\n" );
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document.write( "Simplifying this expression:\r<BR>\n" );
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document.write( "	5y = 83\r<BR>\n" );
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document.write( "or\r<BR>\n" );
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document.write( "	 y = 16.6\r<BR>\n" );
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document.write( "Now, substituting y = 16.6 back into the x expressed as a function of y:\r<BR>\n" );
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document.write( "	x = (-1+2y)/1 = 32.2\r<BR>\n" );
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document.write( " </SPAN>\n" );
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