document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334974>Question 334974</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am 50 yrs old, haven't used algebra since High School and now need it and can't remember what to do to solve the following equations for B and for N:<BR>\n" );
document.write( "0.63B + 0.37N = -8.4   and   0.56B  + 0.44N = -6.6\r<BR>\n" );
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document.write( "I know I need to pick one of the equations, determine the equation just for N, and then replace N in the other equation with that formula to solve for B.    eg, for the first equation  0.37N = -8.4 - 0.63B, now I am stuck as to how to solve for B? Is it N = (-8.4 - 0.63B)/0.37?  How do I perform the calculation to solve for B?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240241 by </B><A HREF=/tutors/aboutme.mpl?userid=priyaasai><B>priyaasai(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=priyaasai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16b^3 </SPAN>\n" );
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