document.write( "Question 335095: A trip of 1080 kms. Part way in car the avged 60 km/hr remainder on train travelling 100 km/hr. Entire trip was 12 hour. What distance travelled in each mode? \n" ); document.write( "
Algebra.Com's Answer #240238 by Fombitz(32388)\"\" \"About 
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Rate*Time=Distance
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\n" ); document.write( "\"60%2AT1=D1\"
\n" ); document.write( "\"100%2AT2=D2\"
\n" ); document.write( "1.\"D1%2BD2=1080\"
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\n" ); document.write( "\"T1%2BT2=12\"
\n" ); document.write( "\"D1%2F60%2BD2%2F100=12\"
\n" ); document.write( "2.\"5D1%2B3D2=3600\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"D1=1080-D2\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"5%281080-D2%29%2B3D2=360\"
\n" ); document.write( "\"5400-5D2%2B3D2=3600\"
\n" ); document.write( "\"-2D2=-1800\"
\n" ); document.write( "\"highlight%28D2=900%29\"km
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\n" ); document.write( "\"D1%2B900=1080\"
\n" ); document.write( "\"highlight%28D1=180%29\"km
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