document.write( "Question 335088: three times a first number is decreased by a second number is 1. the first number increased by twice the second number is 12. what are the numbers? \n" ); document.write( "
Algebra.Com's Answer #240232 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Let the first number be A, second number B.
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"three times a first number is decreased by a second number is 1\"
\n" ); document.write( "1.\"3A-B=1\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "\"the first number increased by twice the second number is 12\"
\n" ); document.write( "2.\"A%2B2B=12\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"3A-B=1\"
\n" ); document.write( "\"B=3A-1\"
\n" ); document.write( "Substitute into eq. 2 for B.
\n" ); document.write( "\"A%2B2B=12\"
\n" ); document.write( "\"A%2B2%283A-1%29=12\"
\n" ); document.write( "\"A%2B6A-2=12\"
\n" ); document.write( "\"7A=14\"
\n" ); document.write( "\"highlight%28A=2%29\"
\n" ); document.write( "Now go back and solve for B.
\n" ); document.write( "\"B=3A-1\"
\n" ); document.write( "\"B=3%282%29-1\"
\n" ); document.write( "\"B=6-1\"
\n" ); document.write( "\"highlight%28B=5%29\"
\n" ); document.write( "
\n" );