document.write( "Question 335151: solve ethe linear system by using substitution:
\n" ); document.write( "6x-y=-35
\n" ); document.write( "5x-2y=-35 \n" ); document.write( "
Algebra.Com's Answer #240210 by benazir.sj@gmail.com(109)\"\" \"About 
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6x-y=-35-------------(1)\r
\n" ); document.write( "\n" ); document.write( "5x-2y=-35-------------(2)\r
\n" ); document.write( "\n" ); document.write( " since both the equations are equal to -35
\n" ); document.write( "(1)=(2)\r
\n" ); document.write( "\n" ); document.write( "6x-y =5x-2y
\n" ); document.write( "6x-5x=y-2y
\n" ); document.write( "x=-y
\n" ); document.write( "now substitute the value of x in any one of the equation\r
\n" ); document.write( "\n" ); document.write( "x=-y
\n" ); document.write( "6x-y= -35
\n" ); document.write( "6(-y) -y=-35
\n" ); document.write( "-7y = -35
\n" ); document.write( "y=-35/-7
\n" ); document.write( "y=5\r
\n" ); document.write( "\n" ); document.write( "put y = 5 in (1)\r
\n" ); document.write( "\n" ); document.write( "6x-y =-35
\n" ); document.write( "6x-5=-35\r
\n" ); document.write( "\n" ); document.write( "6x =-35+5
\n" ); document.write( "6x=-30
\n" ); document.write( "x= -30/6
\n" ); document.write( "x=-5\r
\n" ); document.write( "\n" ); document.write( "ie,
\n" ); document.write( "x= -5
\n" ); document.write( "and y= 5\r
\n" ); document.write( "\n" ); document.write( "Proof:\r
\n" ); document.write( "\n" ); document.write( "6x-y=-35
\n" ); document.write( "6(-5) -5 =-35
\n" ); document.write( "-30-5=-35
\n" ); document.write( "-35=-35
\n" ); document.write( "or
\n" ); document.write( " 5x-2y =-35
\n" ); document.write( "5(-5) -2*5 =-35
\n" ); document.write( "-25-10 =-35
\n" ); document.write( "-35=-35
\n" ); document.write( "LHS =RHS \n" ); document.write( "
\n" );