document.write( "Question 335160: 2y2-2y +37=(y-5)2
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Algebra.Com's Answer #240205 by benazir.sj@gmail.com(109)\"\" \"About 
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2y^2-2y +37=(y-5)^2
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\n" ); document.write( "\n" ); document.write( "(y-5)^2 = y^2 -10y+25\r
\n" ); document.write( "\n" ); document.write( "2y^2 -2y +37 = y^2 -10y +25
\n" ); document.write( "simplify \r
\n" ); document.write( "\n" ); document.write( "2y^2-y^2 -2y +10y +37-25 =0
\n" ); document.write( "y^2+8y +12=0
\n" ); document.write( "now factor this equation\r
\n" ); document.write( "\n" ); document.write( "y^2+8y+12 =0
\n" ); document.write( "y^2 +6y+2y+12 =0
\n" ); document.write( "y(y+6) +2(y+6) =0
\n" ); document.write( "(y+2)(y+6) =0
\n" ); document.write( "y+2=0 or y+6 =0
\n" ); document.write( " y=-2 or y=-6\r
\n" ); document.write( "\n" ); document.write( "therefore the value of y is\r
\n" ); document.write( "\n" ); document.write( "y= -2 or -6
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