document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=335156>Question 335156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question\r<BR>\n" );
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document.write( "Equations 4a + 3b = 27 and 5a - 2b = 28 \r<BR>\n" );
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document.write( "I solved a to = 6 and b = 1 \r<BR>\n" );
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document.write( "Graph both equations on the same set of axes. Include the vertical and horizontal intercepts for each straight line. \r<BR>\n" );
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document.write( "I hope someone can help me. Thanks <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #240197 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=240197\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "You have correctly solved for the ordered pair that is the solution set to your system of equations.  Now for the graphing:\r<BR>\n" );
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document.write( "Start with either one of your equations.\r<BR>\n" );
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document.write( "<b>Step 1.</b>  Pick a value for <i>a</i>.  It can be anything you like, but 0, 1, or some other small integer usually works well and makes the arithmetic easier.\r<BR>\n" );
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document.write( "<b>Step 2.</b>  Substitute that value in place of <i>a</i> in your equation.  Do the arithmetic and determine the value of <i>b</i> that results.\r<BR>\n" );
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document.write( "<b>Step 3.</b>  Take the value of <i>a</i> that you selected for step 1 and the value of <i>b</i> that you calculated in step 2 and form an ordered pair (<i>a</i>,<i>b</i>).\r<BR>\n" );
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document.write( "<b>Step 4.</b>  Plot the ordered pair from Step 3 on your graph.  Since we chose to make the ordered pair in alphabetical order,  the <i>a</i> value is the distance right or left along the horizontal axis and the <i>b</i> value is the distance up or down along the vertical axis.\r<BR>\n" );
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document.write( "<b>Step 5.</b>  Repeat steps 1 through 4 with a different value for <i>a</i>.\r<BR>\n" );
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document.write( "<b>Step 6.</b>  Draw a line across your graph that passes through the two points that you plotted.\r<BR>\n" );
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document.write( "<b>Step 7.</b>  Repeat steps 1 through 6 using the other equation.\r<BR>\n" );
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document.write( "The point where the lines intersect is the solution, because the coordinates of that point will satisfy (read: make true) both of your equations.  You need to determine, by inspection of the graph, what the coordinates of that point are and report your answer as an ordered pair, (<i>a</i>,<i>b</i>), using those coordinates.  To check your answer, you should substitute this set of coordinates into each of your original equations and verify that you have a true statement for each of the equations.\r<BR>\n" );
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document.write( "The point where a line crosses the horizontal axis is the <i>a</i> intercept, and the ordered pair is of the form (<i><IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \alpha\"></i>,<i>0</i>).  The <i>b</i> intercept, (<i>0</i>,<i><IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \beta\"></i>), is where the line crosses the vertical axis. \r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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