document.write( "Question 335064: Someone please show me how to do these so I can help my son\r
\n" ); document.write( "\n" ); document.write( "-1/5y=-6\r
\n" ); document.write( "\n" ); document.write( "3/4z= -5 1/2\r
\n" ); document.write( "\n" ); document.write( "-2/3t=72
\n" ); document.write( "

Algebra.Com's Answer #240129 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
-1/5y=-6
\n" ); document.write( "Assuming you mean (-1/5)y and not -1/(5y):
\n" ); document.write( "Multiply by -1
\n" ); document.write( "(1/5)y = 6
\n" ); document.write( "Multiply by 5
\n" ); document.write( "y = 30
\n" ); document.write( "-----------
\n" ); document.write( "3/4z= -5 1/2
\n" ); document.write( "(3/4)z = -11/2
\n" ); document.write( "Multiply by 4
\n" ); document.write( "3z = -22
\n" ); document.write( "Divide by 3
\n" ); document.write( "z = -22/3
\n" ); document.write( "------------
\n" ); document.write( "-2/3t=72
\n" ); document.write( "Multiply by 3
\n" ); document.write( "-2t = 216
\n" ); document.write( "Divide by -2
\n" ); document.write( "t = -108
\n" ); document.write( "
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