document.write( "Question 335017: if i am teatching a class how would i teatch them how to solve 3-5(x+2)=3(x+1)+6
\n" ); document.write( "please include your work at each step of the process along with the final answer. \n" ); document.write( "
Algebra.Com's Answer #240091 by tinbar(133)\"\" \"About 
You can put this solution on YOUR website!
firstly, you should probably not teach the class if you can't solve this question on your own\r
\n" ); document.write( "\n" ); document.write( "secondly, the solution: you would tell your students this is an equation with only one variable to solve and to solve it, we need to group common terms together and simplify as best as we can\r
\n" ); document.write( "\n" ); document.write( "3-5(x+2)=3(x+1)+6
\n" ); document.write( "3-(5x+10)=(3x+3)+6
\n" ); document.write( "3-5x-10=3x+3+6
\n" ); document.write( "-7-5x=3x+9
\n" ); document.write( "...now the tricky part, we need to have all the x's on one side and anything not x on the other, in this case, i'm going to move all x's to the left side and anything else to the right\r
\n" ); document.write( "\n" ); document.write( "-5x-3x=9+7
\n" ); document.write( "-8x=16
\n" ); document.write( "x=16/-8
\n" ); document.write( "x=-2\r
\n" ); document.write( "\n" ); document.write( "now to check that this satisfies the original question on both sides
\n" ); document.write( "left side: 3-5(-2+2)=3-5(0) = 3
\n" ); document.write( "right side: 3(-2+1)+6 = 3(-1)+6 = -3+6 = 3\r
\n" ); document.write( "\n" ); document.write( "x=-2 works!
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