document.write( "Question 38519: i need this answer right away thank you!\r
\n" );
document.write( "\n" );
document.write( "the perimeter of a rectangle is 56 inches. the length is 5 less than the width find the demensions. \n" );
document.write( "
Algebra.Com's Answer #24009 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! Perimeter = 2l + 2w \n" ); document.write( "Where the length = (w-5) \n" ); document.write( "Where the width = (w) \n" ); document.write( "56 = 2(w-5) + 2(w) \n" ); document.write( "56 = 2w - 10 + 2w \n" ); document.write( "66 = 4w \n" ); document.write( "16.5 = w \n" ); document.write( "11.5 = l \n" ); document.write( "Doesn't the length's measure generally is greater than the width? \n" ); document.write( " |