document.write( "Question 334974: I am 50 yrs old, haven't used algebra since High School and now need it and can't remember what to do to solve the following equations for B and for N:
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document.write( "0.63B + 0.37N = -8.4 and 0.56B + 0.44N = -6.6\r
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document.write( "I know I need to pick one of the equations, determine the equation just for N, and then replace N in the other equation with that formula to solve for B. eg, for the first equation 0.37N = -8.4 - 0.63B, now I am stuck as to how to solve for B? Is it N = (-8.4 - 0.63B)/0.37? How do I perform the calculation to solve for B? \n" );
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Algebra.Com's Answer #240052 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your first step was correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now take the right hand side mess and replace N in the second equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you have an equation, albeit an extremely ugly one, in one variable that can be solved by ordinary algebraic means. Once you have a value for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is mostly just nasty arithmetic. Enjoy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |