document.write( "Question 334965: Two planes left an airport at noon One flew east at a certain speed and the other flew west at twice the speed The planes were 2700 miles apart in 3 hours How fast was each plane flying? \n" ); document.write( "
Algebra.Com's Answer #240038 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If the planes were 2700 miles apart after 3 hours, then they were 900 miles apart after 1 hour which means their speed relative to each other is 900 miles per hour. One-third of 900 is 300 and two-thirds is 600, so the slow plane must be going 300 miles per hour and the fast plane 600 miles per hour.\r
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\n" ); document.write( "\n" ); document.write( "Check, after 3 hours the slow plane will have traveled 900 miles, and the fast plane will have traveled 1800 miles and 900 plus 1800 equals 2700 -- answer checks.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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