document.write( "Question 334816: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? I need to translate this problem into a pair of linear equations in two variables. Can anyone help? \n" ); document.write( "
Algebra.Com's Answer #239957 by Fombitz(32388)\"\" \"About 
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Let A be the number of liters of 40%-alcohol solution.
\n" ); document.write( "Look at the concentration equation.
\n" ); document.write( "\"%2840%2F100%29A%2B%2880%2F100%29%2810%29=%2860%2F100%29%28A%2B10%29\"
\n" ); document.write( "\"40A%2B800=60%28A%2B10%29\"
\n" ); document.write( "\"40A%2B800=60A%2B600\"
\n" ); document.write( "\"-20A=-200\"
\n" ); document.write( "\"A=10\"
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\n" ); document.write( "10 liters of 40% solution plus 10 liters of 80% will provide 20 liters of 60% solution.
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