document.write( "Question 334816: How many liters of a 40%-alcohol solution must be mixed with 10 liters of a solution that is 80% alcohol to get a solution that is 60% alcohol? I need to translate this problem into a pair of linear equations in two variables. Can anyone help? \n" ); document.write( "
Algebra.Com's Answer #239957 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! Let A be the number of liters of 40%-alcohol solution. \n" ); document.write( "Look at the concentration equation. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "10 liters of 40% solution plus 10 liters of 80% will provide 20 liters of 60% solution. \n" ); document.write( " \n" ); document.write( " |