document.write( "Question 334853: In a walkathon to raise money for charity Alicia walked a certain distance at 5 mi/h and then jogged twice that distance at 8 mi/h. Her total walking and jogging was 2 hours 15 minutes. How many miles was the walkathon? \n" ); document.write( "
Algebra.Com's Answer #239941 by CharlesG2(834)\"\" \"About 
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\"In a walkathon to raise money for charity Alicia walked a certain distance at 5 mi/h and then jogged twice that distance at 8 mi/h. Her total walking and jogging was 2 hours 15 minutes. How many miles was the walkathon?\"\r
\n" ); document.write( "\n" ); document.write( "D distance = R rate * T time\r
\n" ); document.write( "\n" ); document.write( "let d = distance walked at 5 mph (mph = mi/h)
\n" ); document.write( "let 2d = distance jogged at 8 mph
\n" ); document.write( "let 3d = total distance in 2.25 hours (15 minutes = 0.25 hours)
\n" ); document.write( "let t = time walking
\n" ); document.write( "let 2.25 - t = time jogging\r
\n" ); document.write( "\n" ); document.write( "d = 5 * t
\n" ); document.write( "2d = 8 * (2.25 - t) = 18 - 8t --> d = 9 - 4t (dividing both sides by 2)\r
\n" ); document.write( "\n" ); document.write( "5t = 9 - 4t (setting the 2 d's equal and solving for t)
\n" ); document.write( "9t = 9
\n" ); document.write( "t = 1 hour\r
\n" ); document.write( "\n" ); document.write( "if t = 1 hour then d = 5 miles, then 3d = 15 miles\r
\n" ); document.write( "\n" ); document.write( "walkathon is 15 miles
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