document.write( "Question 38509: i need help with this uhmm....word problem. Please and Thank You!!!
\n" ); document.write( "A dealer has some hard candy worth $2.00 a pound and some worth $3.00 a pound. He wishes to make a mixture of 80 pounds that he can sell for $2.20 a pound. How many pounds of each candy does he need?\r
\n" ); document.write( "\n" ); document.write( "thank you so much..... \n" ); document.write( "
Algebra.Com's Answer #23994 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A dealer has some hard candy worth $2.00 a pound and some worth $3.00 a pound. He wishes to make a mixture of 80 pounds that he can sell for $2.20 a pound. How many pounds of each candy does he need?\r
\n" ); document.write( "\n" ); document.write( "Let amount of $2 hard candy be \"x\".
\n" ); document.write( "Then amount of $3 hard candy is \"80-x\"
\n" ); document.write( "Value of $2 candy is 2x dollars
\n" ); document.write( "Value of $3 candy is 3(80-x)=240-3x dollars
\n" ); document.write( "Value of the mixed candy is 2.2(80)=176 dollars
\n" ); document.write( "EQUATION:
\n" ); document.write( "Value of $2 candy + Value of $3 candy = Value of mixed candy
\n" ); document.write( " 2x + 240-3x=176
\n" ); document.write( "-x=-64
\n" ); document.write( " x= 64 pounds of $2 hard candy
\n" ); document.write( "80-x=16 pounds of $3 hard candy.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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