document.write( "Question 334845: if the square box is 20 feet from corner to corner what would be the dimensions of the square in sq yds \n" ); document.write( "
| Algebra.Com's Answer #239937 by solver91311(24713)     You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The diagonal of a square creates two isosceles right triangles with the diagonal of the square as the hypotenuse. The three sides of an isosceles right triangle are in proportion:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Verification of this claim is left as an exercise for the student. (Hint: use Pythagoras with an isosceles triangle with hypotenuse of 1 and sides of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, if the diagonal of the square is 20, then the hypotenuse of the triangle is 20 and the side of the triangle must be \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The area of a square is the measure of the side of the square squared. So calculate:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( "  \n" ); document.write( " \n" ); document.write( " |