document.write( "Question 4846: four oranges and five apples cost $3.56 three oranges and four apples cost $2.76. find the cost of an orange and the cost of an apple. \n" ); document.write( "
Algebra.Com's Answer #2399 by Abbey(339)\"\" \"About 
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Let the cost of oranges be x
\n" ); document.write( "Let the cost of apples be y
\n" ); document.write( "Then:
\n" ); document.write( "4x+5Y=3.56
\n" ); document.write( "4x+3Y=2.76
\n" ); document.write( "subtract the second equation from the first
\n" ); document.write( "2y=.80
\n" ); document.write( "divide both sides by 2
\n" ); document.write( "y=.40
\n" ); document.write( "put this back into either of the original equations to find out how much an orange costs
\n" ); document.write( "4x+5(.40)=3.56
\n" ); document.write( "4x+2.00=3.56
\n" ); document.write( "4x=1.56
\n" ); document.write( "x=.39 cents
\n" ); document.write( "check this answer by using the other equation:
\n" ); document.write( "4(.39)+3(.40)=2.76
\n" ); document.write( "1.56+1.20=2.76
\n" ); document.write( "This is true, so oranges cost .39 cents each and apples cost .40 cents each.\r
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