document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=334755>Question 334755</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f(x)=x²+3, and g(x)=x-1 then f(g(x)) is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #239898 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=239898\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the value of g(x) and plug it into every x that you see for f(x).\r<BR>\n" );
document.write( "\n" );
document.write( "For f(x) = x^2 + 3, let x = (x - 1) and do the math.\r<BR>\n" );
document.write( "\n" );
document.write( "f(x - 1) = (x - 1)^2 + 3\r<BR>\n" );
document.write( "\n" );
document.write( "f(x - 1) = (x - 1)(x - 1) + 3\r<BR>\n" );
document.write( "\n" );
document.write( "f(x - 1) = x^2 - 2x + 1 + 3\r<BR>\n" );
document.write( "\n" );
document.write( "f(x - 1) = x^2 - 2x + 4\r<BR>\n" );
document.write( "\n" );
document.write( "So, f(g(x)) = x^2 - 2x + 4\r<BR>\n" );
document.write( "\n" );
document.write( "Understand? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );