document.write( "Question 334785: A piece of wire 60cm in length is cut and the resulting two pieces are formed to make a circle and a square. Where should the wire be cut to (a) minimize and (b) maximize the combined area of the circle and the square.
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Algebra.Com's Answer #239883 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Circumference of circle + Perimeter of Square = 60\r\n" );
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document.write( "\"2%2Api%2Ar+%2B+4x\"\"%22%22=%22%22\"\"60\"\r\n" );
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document.write( "Solve for r\r\n" );
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document.write( "\"2%2Api%2Ar\"\"%22%22=%22%22\"\"60-4x\"\r\n" );
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document.write( "Divide through by 2\r\n" );
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document.write( "\"pi%2Ar\"\"%22%22=%22%22\"\"30-2x\"\r\n" );
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document.write( "Multiply both sides by \"1%2Fpi\"\r\n" );
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document.write( "\"r\"\"%22%22=%22%22\"\"1%2Fpi\"\"%2830-2x%29\"\r\n" );
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document.write( "Let y = Area of circle + Area of square\r\n" );
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document.write( "    \"y=pi%2Ar%5E2%2Bx%5E2\"\r\n" );
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document.write( "We need to substitute for \"r%5E2\"\r\n" );
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document.write( "\"r\"\"%22%22=%22%22\"\"1%2Fpi\"\"%2830-2x%29\"\r\n" );
document.write( "\"r%5E2\"\"%22%22=%22%22\"\"1%2Fpi%5E2\"\"%2830-2x%29%5E2\"\r\n" );
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document.write( "Substituting:\r\n" );
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document.write( "\"y=pi%2A%22%22\"\"1%2Fpi%5E2\"\"%2830-2x%29%5E2%2Bx%5E2\"\r\n" );
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document.write( "\"y=cross%28pi%29%2A%22%22\"\"1%2Fpi%5Ecross%282%29\"\"%2830-2x%29%5E2%2Bx%5E2\"\r\n" );
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document.write( "\"y=1%2Fpi\"\"%2830-2x%29%5E2%2Bx%5E2\"\r\n" );
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document.write( "[If you were taking calculus you would take the derivative here and set it\r\n" );
document.write( "equal to 0, but I am assuming that you are taking college algebra, so you must\r\n" );
document.write( "use the vertex formula.]\r\n" );
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document.write( "\"y=1%2Fpi\"\"%28900-120x%2B4x%5E2%29%2Bx%5E2\"\r\n" );
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document.write( "\"y=900%2Fpi-%28120%2Fpi%29x%2B%284%2Fpi%29x%5E2%2Bx%5E2\"\r\n" );
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document.write( "\"y=900%2Fpi-%28120%2Fpi%29x%2B%284%2Fpi%2B1%29x%5E2\"\r\n" );
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document.write( "or in descending powers:\r\n" );
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document.write( "\"y+=+%284%2Fpi%2B1%29x%5E2-%28120%2Fpi%29x%2B900%2Fpi\"\r\n" );
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document.write( "The coefficient of \"x%5E2\" is positive so this represents\r\n" );
document.write( "a parabola that opens upward, so its vertex will be at a minimum\r\n" );
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document.write( "To find the x-cordinate of the vertex, we use the vertex formula\r\n" );
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document.write( "x-coordinate of vertex = \"-b%2F%282a%29\"\r\n" );
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document.write( "x-coordinate of vertex = \"-%28%28-120%29%2Fpi%29%2F%282%284%2Fpi%2B1%29%29\"\"%22%22=%22%22\"\"%28%28120%29%2Fpi%29%2F%282%284%2Fpi%2B1%29%29\"\"%22%22=%22%22\"\"%28%28120%29%2Fpi%29\"\"%22%F7%22\"\"%282%284%2Fpi%2B1%29%29\"\"%22%22=%22%22\"\"%28%28120%29%2Fpi%29\"\"%22%F7%22\"\"%282%28%284%2Bpi%29%2Fpi%29%29\"\"%22%22=%22%22\"\"%28%28120%29%2Fpi%29\"\"%22%F7%22\"\"%28%282%284%2Bpi%29%29%2Fpi%29%29\"\r\n" );
document.write( "\"%22%22=%22%22\"\"%28%28120%29%2Fpi%29\"\"%22%D7%22\"\"%28pi%2F%282%284%2Bpi%29%29%29%29\"\"%22%22=%22%22\"\"%28%28120%29%2Fcross%28pi%29%29\"\"%22%D7%22\"\"%28cross%28pi%29%2F%282%284%2Bpi%29%29%29%29\"\"%22%22=%22%22\"\"%22%D7%22\"\"%28120%2F%282%284%2Bpi%29%29%29%29\"\"%22%22=%22%22\"\"60%2F%284%2Bpi%29\"\r\n" );
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document.write( "So for the minimum area, the side of a square will be \"60%2F%284%2Bpi%29\" cm.\r\n" );
document.write( "That is approximately 8.401487303 cm.\r\n" );
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document.write( "We will need to cut the wire at 4 times the side of the square.\r\n" );
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document.write( "So we must cut the wire at \"4\"\"%22%D7%22\"\"60%2F%284%2Bpi%29\" or \"240%2F%284%2Bpi%29\" \r\n" );
document.write( "or about 33.60594921 cm from one end and, subtracting from 60,\r\n" );
document.write( "26.39405079 cm from the other end.\r\n" );
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document.write( "Now for the maximum area. The problem is only defined for \"0+%3C=+x+%3C=+15\"\r\n" );
document.write( "When x=0, the square shrinks to 0 and the whole 60cm wire is made into a\r\n" );
document.write( "circle.  When x=15, making the perimeter of the square 60 cm, the circle\r\n" );
document.write( "shrinks to 0 and the whole 60cm wire is made into a square.  Since the parabola\r\n" );
document.write( "opens upward, the maximum value is at one endpoint of the interval, either when\r\n" );
document.write( "x=0 or when x=15.  It is well known that if a piece of wire is bent into a\r\n" );
document.write( "circle or a square, the circle will have more area, so we could just assume the\r\n" );
document.write( "maximum area would be when we \"cut\" the wire 0, or no, centimeters from the\r\n" );
document.write( "end, and bend the whole wire into a circle. That is we don't cut the wire at\r\n" );
document.write( "all.\r\n" );
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document.write( "Edwin

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